document.write( "Question 267340: \"log%282%2C%2848x%5E3%29%29-log%282%2C%2812x%5E2%29%29=8\"
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Algebra.Com's Answer #196246 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
we start with
\n" ); document.write( "\"log%282%2C%2848x%5E3%29%29-log%282%2C%2812x%5E2%29%29=8\"
\n" ); document.write( "step 1 - subtraction of logs means divide the terms as
\n" ); document.write( "\"log%282%2C%2848x%5E3%29%2F%2812x%5E2%29%29=8\"
\n" ); document.write( "step 2 reduce the fraction to get
\n" ); document.write( "\"log%282%2C%284x%29%29=8\"
\n" ); document.write( "step 3 - rewrite using exponents as
\n" ); document.write( "\"2%5E8+=+4x\"
\n" ); document.write( "step 4 - divide to get
\n" ); document.write( "\"x+=+64\"
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