document.write( "Question 267302: Find the equation of the line containing the point (2,-5) and perpendicular to the line y=5/2x-4. \n" ); document.write( "
Algebra.Com's Answer #196234 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Do it like this: \n" ); document.write( "------------------------- \n" ); document.write( "A line and a point example. \n" ); document.write( "Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2) \n" ); document.write( "----------------- \n" ); document.write( "Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y. \n" ); document.write( "9x+3y = 36 \n" ); document.write( "3y= - 9x + 36 \n" ); document.write( "y = -3x + 13 \n" ); document.write( "The slope, m = -3 \n" ); document.write( "------------------ \n" ); document.write( "The slope of lines parallel have the same slope. \n" ); document.write( "The slope of lines perpendicular is the negative inverse, m = +1/3 \n" ); document.write( "---------------- \n" ); document.write( "Use y = mx + b and the point (1,2) to find b. \n" ); document.write( "2 = (1/3)*1 + b \n" ); document.write( "b = 5/3 \n" ); document.write( "The equation is y = (1/3)x + 5/3 (slope-intercept form) \n" ); document.write( "x - 3y = -5 (standard form) \n" ); document.write( "------------------------ \n" ); document.write( "For further assistance, or to check your work, email me via the thank you note. \n" ); document.write( " |