document.write( "Question 267345: please solve\r
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document.write( "a solution containing 30% juice is mixed with a solution containing 10% juice to make 100 gallons of solution that makes 12% juice.How much of the 30% solution was used? \n" );
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Algebra.Com's Answer #196230 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! In words: \n" ); document.write( "(gallons of juice in 1st solution + gallons of juice in 2nd solution / (gallons of final solution) = 12% \n" ); document.write( "Let \n" ); document.write( "Let \n" ); document.write( "given: \n" ); document.write( "(1) \n" ); document.write( "------------------ \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(2) \n" ); document.write( "Now subtract (1) from (2) \n" ); document.write( "(2) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and, since \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "10 gallons of the 30% solution were needed \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |