document.write( "Question 267345: please solve\r
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document.write( "a solution containing 30% juice is mixed with a solution containing 10% juice to make 100 gallons of solution that makes 12% juice.How much of the 30% solution was used? \n" );
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Algebra.Com's Answer #196226 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .30x+.10(100-x)=.12*100 \n" ); document.write( ".30x+10-.10x=12 \n" ); document.write( ".20x=12-10 \n" ); document.write( ".20x=2 \n" ); document.write( "x=2/.2 \n" ); document.write( "x=10 gallons of 30% solution is used. \n" ); document.write( "100-10=90 gallons 0f 10% is used. \n" ); document.write( "Proof: \n" ); document.write( ".30*10+.10*90=.12*100 \n" ); document.write( "3+9=12 \n" ); document.write( "12=12\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |