document.write( "Question 267239: Identify the conic x^2-4y^2-4x-8y-4=0 and find its center and foci \n" ); document.write( "
Algebra.Com's Answer #196225 by drk(1908)\"\" \"About 
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This conic is a hyperbola. The adjusted equation after completing the square is
\n" ); document.write( "\"%28x-2%29%5E2+-+4%28y%2B2%29%5E2+=+4+%2B4%2B4\"
\n" ); document.write( "or
\n" ); document.write( "\"%28x-2%29%5E2%2F12+-+%28y%2B2%29%5E2%2F3+=+1\"
\n" ); document.write( "The center is (2, -2)
\n" ); document.write( "The foci are sqrt(12+3) = sqrt(15)
\n" ); document.write( "The coordinates of the foci are
\n" ); document.write( "(2 +- sqrt(15), -2)
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