document.write( "Question 267333: Traveling against the current, the scouts paddled 20 km in 6hrs. The return trip with the current took 1hr. less. Find the scout's rate of paddling in still water, and the rate of the current.\r
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Algebra.Com's Answer #196223 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The equation for paddling against the current is: \n" ); document.write( " \n" ); document.write( "The equation for paddling with the current is: \n" ); document.write( " \n" ); document.write( "where \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------------- \n" ); document.write( "given: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------ \n" ); document.write( "Plugging in numbers: \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "------------------------ \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "I'll multiply both sides of (2) by \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "Now add (1) and (2) \n" ); document.write( "(2) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "From (2): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In still water, they can paddle 11/3 km/hr \n" ); document.write( "The speed of the current is 1/3 km/hr \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |