document.write( "Question 267227: Fran received $113 per year in simple interest from investing $1300.00 Part is invested at 7% and part at 8% and part at 9%. There is 800 more invested at 9% than 8%. Find the amount invested at 9%. \n" ); document.write( "
Algebra.Com's Answer #196180 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Let \n" ); document.write( "Let \n" ); document.write( "given: \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "(3) \n" ); document.write( "--------------------- \n" ); document.write( "Multiply both sides of (2) by \n" ); document.write( "(2) \n" ); document.write( "Multiply both sides of (1) by \n" ); document.write( "and subtract (1) from (2) \n" ); document.write( "(2) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( "And from (3): \n" ); document.write( " \n" ); document.write( "By substitution: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "$1000 was invested @ 9% \n" ); document.write( "check answer: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |