document.write( "Question 267227: Fran received $113 per year in simple interest from investing $1300.00 Part is invested at 7% and part at 8% and part at 9%. There is 800 more invested at 9% than 8%. Find the amount invested at 9%. \n" ); document.write( "
Algebra.Com's Answer #196180 by josmiceli(19441)\"\" \"About 
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Let \"a\" = amount invested @ 7%
\n" ); document.write( "Let \"b\" = amount invested @ 8%
\n" ); document.write( "Let \"c\" = amount invested @ 9%
\n" ); document.write( "given:
\n" ); document.write( "(1) \"a+%2B+b+%2B+c+=+1300\"
\n" ); document.write( "(2) \".07a+%2B+.08b+%2B+.09c+=+113\"
\n" ); document.write( "(3) \"c+=+b+%2B+800\"
\n" ); document.write( "---------------------
\n" ); document.write( "Multiply both sides of (2) by \"100\"
\n" ); document.write( "(2) \"7a+%2B+8b+%2B+9c+=+11300\"
\n" ); document.write( "Multiply both sides of (1) by \"7\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"7a+%2B+8b+%2B+9c+=+11300\"
\n" ); document.write( "(1) \"-7a+-+7b+-+7c+=+-9100\"
\n" ); document.write( "\"b+%2B+2c+=+2200\"
\n" ); document.write( "And from (3):
\n" ); document.write( "\"b+=+c+-+800\"
\n" ); document.write( "By substitution:
\n" ); document.write( "\"c+-+800+%2B+2c+=+2200\"
\n" ); document.write( "\"3c+=+3000\"
\n" ); document.write( "\"c+=+1000\"
\n" ); document.write( "$1000 was invested @ 9%
\n" ); document.write( "check answer:
\n" ); document.write( "\"b+=+c+-+800\"
\n" ); document.write( "\"b+=+1000+-+800\"
\n" ); document.write( "\"b+=+200\"
\n" ); document.write( "\"a+%2B+b+%2B+c+=+1300\"
\n" ); document.write( "\"a+%2B+200+%2B+1000+=+1300\"
\n" ); document.write( "\"a+=+1300+-+1200\"
\n" ); document.write( "\"a+=+100\"
\n" ); document.write( "and
\n" ); document.write( "\".07%2A100+%2B+.08%2A200+%2B+.09%2A1000+=+113\"
\n" ); document.write( "\"7+%2B+16+%2B+90+=+113\"
\n" ); document.write( "\"113+=+113\"
\n" ); document.write( "OK\r
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