document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33224>Question 33224</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In any triangle, A=62 degrees, c=15, and b=12; find the area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19616 by </B><A HREF=/tutors/aboutme.mpl?userid=sarah_adam><B>sarah_adam(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarah_adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Side Angle Side :<BR>\n" );
document.write( "when length of two sides and one angle is given then the formula for calculating area is A = (1/2 *a*b* sin theta )where a and b are the sides of the triangle and theta is the angle included between the two sides<BR>\n" );
document.write( "here sides are 15 and 12 and theta is 62 degrees<BR>\n" );
document.write( "A = 1/2 * 15 *12 *sin(62)<BR>\n" );
document.write( "A = 80 sin (62)<BR>\n" );
document.write( "A = 80 * 0.88 (sin 62 = 0.88)<BR>\n" );
document.write( "A = 70.63 sq units\r<BR>\n" );
document.write( "\n" );
document.write( "(please verify the value of Sin 62) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );