document.write( "Question 267131: A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes 1/2 hr longer than he would if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y? \n" ); document.write( "

Algebra.Com's Answer #196136 by Alan3354(69443) $\"\"$ $\"About$

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A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes 1/2 hr longer than he would if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y?
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\n" ); document.write( "t1 = d/50 + d/40 = 9d/200
\n" ); document.write( "t2 = 2d/45
\n" ); document.write( "t2 = t1 - 0.5
\n" ); document.write( "--------------
\n" ); document.write( "Sub for t2 in 2nd eqn
\n" ); document.write( "t1-0.5 = 2d/45
\n" ); document.write( "t1 = 2d/45 + 0.5 = 9d/200
\n" ); document.write( "---------------------
\n" ); document.write( "2d/45 + 0.5 = 9d/200
\n" ); document.write( "200*2d + 4500 = 9d*45
\n" ); document.write( "400d - 405d = -4500
\n" ); document.write( "-5d = -4500
\n" ); document.write( "d = 900 miles
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\n" ); document.write( "I know it's right because I've been to those towns.
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