document.write( "Question 267085: The length of the hypotenuse of a right-angled triangle is 240 units. The perimeter of the given triangle is a perfect square. If the perimeter of the given triangle is greater than 550 units, then which of the following can be the length of a side of the given right-angled triangle? \n" ); document.write( "
Algebra.Com's Answer #196120 by CharlesG2(834)\"\" \"About 
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The length of the hypotenuse of a right-angled triangle is 240 units. The perimeter of the given triangle is a perfect square. If the perimeter of the given triangle is greater than 550 units, then which of the following can be the length of a side of the given right-angled triangle? \r
\n" ); document.write( "\n" ); document.write( "a^2 + b^2 = c^2 = 240^2 = 57600
\n" ); document.write( "a + b + 240 > 550
\n" ); document.write( "a + b > 310
\n" ); document.write( "a > 310 - b
\n" ); document.write( "b > 310 - a
\n" ); document.write( "first perfect square after 550 is 24^2 which is 576
\n" ); document.write( "set a + b + 240 equal to 576
\n" ); document.write( "a + b = 336 (576-240=336)
\n" ); document.write( "a = 336 - b
\n" ); document.write( "b = 336 - a (use this to subsitute)
\n" ); document.write( "a^2 + (336 - a)^2 = 57600
\n" ); document.write( "a^2 + 112896 - 672a + a^2 = 57600 (336^2=112896, 2*336=672)
\n" ); document.write( "2a^2 - 672a + 55296 = 0
\n" ); document.write( "a^2 - 336a + 27648 = 0
\n" ); document.write( "27648 = 2 * 13824
\n" ); document.write( "13824 = 2 * 6912
\n" ); document.write( "6912 = 2 * 3456
\n" ); document.write( "3456 = 2 * 1728
\n" ); document.write( "1728 = 2 * 864
\n" ); document.write( "864 = 2 * 432
\n" ); document.write( "432 = 2 * 216
\n" ); document.write( "216 = 2 * 108
\n" ); document.write( "108 = 2 * 54
\n" ); document.write( "54 = 2 * 27
\n" ); document.write( "27 = 3 * 3 * 3
\n" ); document.write( "27648 = 2^10 * 3^3 = 1024 * 27
\n" ); document.write( "144 = 2^4 * 3^2
\n" ); document.write( "27648 = 2^4 * 3^2 * 2^6 * 3 = 16 * 9 * 64 * 3 = 144 * 192
\n" ); document.write( "144 + 192 = 336
\n" ); document.write( "(a - 192)(a - 144)=0
\n" ); document.write( "a = 144 or a = 192
\n" ); document.write( "now b = 336 - a
\n" ); document.write( "so b = 192 or b = 144
\n" ); document.write( "side a needs to be a minimum of 144, and side b needs to be a minimum of 192\r
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