document.write( "Question 33194: Find the center of an ellipse with the equation \"9x%5E2+%2B+16y%5E2+-+18x+%2B+64y+=+71\" \n" ); document.write( "
Algebra.Com's Answer #19610 by mukhopadhyay(490)\"\" \"About 
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9x^2+16y^2-18x+64y=71
\n" ); document.write( "=> 9(x^2-2x)+16(y^2+4y) = 71
\n" ); document.write( "=> 9[(x-1)^2-1]+16[(y+2)^2-4] = 71
\n" ); document.write( "=> 9(x-1)^2+16(y+2)^2 = 71+9+64
\n" ); document.write( "=> 9(x-1)^2+16(y+2)^2 = 144 (same as 12^2)
\n" ); document.write( "=> (x-1)^2/4^2 + (y+2)^2/3^2 = 1
\n" ); document.write( "The center of an ellipse of form (x-h)^2/a^2 + (y-k)^2/b^2 = 1 is at (h,k)
\n" ); document.write( "So, the center of the specified ellipse is at (1,-2).
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