document.write( "Question 33194: Find the center of an ellipse with the equation \n" );
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Algebra.Com's Answer #19610 by mukhopadhyay(490)![]() ![]() ![]() You can put this solution on YOUR website! 9x^2+16y^2-18x+64y=71 \n" ); document.write( "=> 9(x^2-2x)+16(y^2+4y) = 71 \n" ); document.write( "=> 9[(x-1)^2-1]+16[(y+2)^2-4] = 71 \n" ); document.write( "=> 9(x-1)^2+16(y+2)^2 = 71+9+64 \n" ); document.write( "=> 9(x-1)^2+16(y+2)^2 = 144 (same as 12^2) \n" ); document.write( "=> (x-1)^2/4^2 + (y+2)^2/3^2 = 1 \n" ); document.write( "The center of an ellipse of form (x-h)^2/a^2 + (y-k)^2/b^2 = 1 is at (h,k) \n" ); document.write( "So, the center of the specified ellipse is at (1,-2). \n" ); document.write( " |