document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=267117>Question 267117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The shortest side of a triangle is one half the length of the middle side, plus 2 cm.  The longest side of the triangle is one and one-half times the length of the middle side, less 2 cm.  The perimeter of the triangle is 60 cm. How long are each of the sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196094 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196094\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S = (1/2)m + 2<BR>\n" );
document.write( "m = m<BR>\n" );
document.write( "L = (3/2)m  - 2<BR>\n" );
document.write( "P = 60<BR>\n" );
document.write( "----<BR>\n" );
document.write( "P = short + middle + long<BR>\n" );
document.write( "60 = (1/2)m  + 2 + m +(3/2)m - 2<BR>\n" );
document.write( "combine like terms to get<BR>\n" );
document.write( " 60 = 3m<BR>\n" );
document.write( "divide to get<BR>\n" );
document.write( "m = 20<BR>\n" );
document.write( "s = 12<BR>\n" );
document.write( "L = 28 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );