document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=267119>Question 267119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> it took 3 hours to row a boat 18 km against the current. The return trip with the current took 1 1/2 hours. find the speed of the plane in still air.\r<BR>\n" );
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document.write( "I know d = r x t, but I am stuck on how to get the still air. I know to make both equations = to 18, but help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196088 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r*t=d<BR>\n" );
document.write( "r*3=18<BR>\n" );
document.write( "(r-x)*3=18<BR>\n" );
document.write( "r-x=6<BR>\n" );
document.write( "(r+x)*3/2=18<BR>\n" );
document.write( "r+x=12<BR>\n" );
document.write( "r-x=6<BR>\n" );
document.write( "2r=18<BR>\n" );
document.write( "r=9 in still water<BR>\n" );
document.write( "r+x=12<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "current=3 \r<BR>\n" );
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document.write( "I assume they really mean still water not still air and that they mean boat not plane since they left in a boat not plane. </SPAN>\n" );
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