document.write( "Question 267116: The shortest side of a triangle is one half the length of the middle side, plus 2 cm. The longest side of the triangle is one and one-half times the length of the middle side, less 2 cm. The perimeter of the triangle is 60 cm. How long are each of the sides?
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Algebra.Com's Answer #196086 by psbhowmick(878)\"\" \"About 
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Let us suppose that shortest side = x cm, middle side = y cm and longest side = z cm.\r
\n" ); document.write( "\n" ); document.write( "The shortest side of a triangle is one half the length of the middle side, plus 2 cm. This means \"x+=+%281%2F2%29%2Ay+%2B+2\" _____ (1)\r
\n" ); document.write( "\n" ); document.write( "The longest side of the triangle is one and one-half times the length of the middle side, less 2 cm. This means, \"z+=+%283%2F2%29%2Ay+-+2\" ______ (2)\r
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\n" ); document.write( "\n" ); document.write( "Also given, perimeter = 60 cm i.e. \"x+%2B+y+%2B+z+=+60\" _______ (3)\r
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\n" ); document.write( "\n" ); document.write( "Substituting for x and z from (1) and (2) respectively into (3), we have
\n" ); document.write( "\"%281%2F2%29%2Ay+%2B+2+%2B+y+%2B+%283%2F2%29%2Ay+-+2+=+60\"
\n" ); document.write( "\"%281%2F2%29%2Ay+%2B+y+%2B+%283%2F2%29%2Ay+=+60\"
\n" ); document.write( "\"3%2Ay+=+60\"
\n" ); document.write( "\"y=+60%2F3=20\"\r
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\n" ); document.write( "\n" ); document.write( "Hence, \"x+=+%281%2F2%29%2A20+%2B+2+=+12\" and \"z+=+%283%2F2%29%2A20+-+2+=+28\"\r
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\n" ); document.write( "\n" ); document.write( "The sides of the triangle are: 12 cm, 20 cm and 28 cm.
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