document.write( "Question 266905: John can mow 3 yards in 2 hrs while sally can mow 4yards in 3hrs. Working together, how long would it take them to mow 2 yards? \n" ); document.write( "
Algebra.Com's Answer #196021 by josmiceli(19441)\"\" \"About 
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If John can mow 3 yards in 2 hours, then
\n" ); document.write( "he can mow 1 yard in 2/3 hr, because
\n" ); document.write( "(1 yards)/(2/3)hrs = 3 yard/2 hrs
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\n" ); document.write( "If Sally can mow 4 yards in 3 hrs, then
\n" ); document.write( "she can mow 1 yard in 3/4 hrs, since
\n" ); document.write( "(1 yards)/(3/4)hrs = 4 yard/3 hrs
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\n" ); document.write( "Working together, I add their rate of working
\n" ); document.write( "\"3%2F2+%2B+4%2F3+=+2%2Fx\"
\n" ); document.write( "Multiply both sides by \"6x\"
\n" ); document.write( "\"9x+%2B+8x+=+12\"
\n" ); document.write( "\"17x+=+12\"
\n" ); document.write( "\"x+=+12%2F17\" hrs \r
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