document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=266905>Question 266905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John can mow 3 yards in 2 hrs while sally can mow 4yards in 3hrs. Working together, how long would it take them to mow 2 yards? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196018 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> John can mow 3 yards in 2 hrs while sally can mow 4yards in 3hrs. Working together, how long would it take them to mow 2 yards?\r<BR>\n" );
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document.write( "John can mow yards at the rate of 3 yards/2 hours or 3/2 yards per hour.<BR>\n" );
document.write( "Sally can mow yards at 4 yards/3 hours = 4/3 yards per hour.\r<BR>\n" );
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document.write( "Together then they mow at a rate of 3/2 + 4/3 yards per hour. If t is the time needed for them to mow 2 yards then we have:\r<BR>\n" );
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document.write( "2 = (3/2+4/3)*t\r<BR>\n" );
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document.write( "Solve the above for t. </SPAN>\n" );
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