document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=266876>Question 266876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the ratio of the length to the width of a rectangle is 4:3 and the perimeter is 84 centimeters, find its area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195989 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the ratio of the length to the width of a rectangle is 4:3 and the perimeter is 84 centimeters, find its area.\r<BR>\n" );
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document.write( "Let 3x be the width and 4x the length. The ratio is then is 4x/3x = 4/3 or 4:3.\r<BR>\n" );
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document.write( "The perimeter 84 is equal to 2*w + 2*l = 2*3x + 2*4x or:\r<BR>\n" );
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document.write( "84 = 6x + 8x<BR>\n" );
document.write( "14x = 84<BR>\n" );
document.write( "x = 6\r<BR>\n" );
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document.write( "Now you can compute the width, 3x, and the length, 4x.\r<BR>\n" );
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