document.write( "Question 266871: A couple has a 2/3 probability of passing on brown eyes to their children. If they have four children, what is the probability that none of the children will have brown eyes? \r
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document.write( "A) 1/81\r
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document.write( "B) 8/27\r
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document.write( "C) 16/81\r
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document.write( "D) 1/27\r
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document.write( "Thank you :)\r
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Algebra.Com's Answer #195987 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! A couple has a 2/3 probability of passing on brown eyes to their children. If they have four children, what is the probability that none of the children will have brown eyes? \r \n" ); document.write( "\n" ); document.write( "Since the probablility of brown eyes is 2/3 the probability of not brown eyes is 1 - 2/3 = 1/3.\r \n" ); document.write( "\n" ); document.write( "The probability of brown eyes four times is:\r \n" ); document.write( "\n" ); document.write( "(1/3)*(1/3)*(1/3)*(1/3) = 1/3^4 = 1/81 \n" ); document.write( " |