document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=266766>Question 266766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves New York for Boston, 200 miles away, at 4:00 P.M. and averages 60 mph. Another train leaves Boston for New York on an adjacent set of tracks at 3:00 P.M. and averages 50 mph. At what time will the trains meet? (Round to the nearest minute.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195947 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195947\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is an RTD problem. Here is a table based on the given information:<BR>\n" );
document.write( "trains . . . . . . . . rate . . . . . . . . . .time . . . . . . . . . .distance<BR>\n" );
document.write( "to boston . . . . . .60 . . . . . . . . . . .t . . . . . . . . . . . . . . .60t = 200<BR>\n" );
document.write( "to NY . . . . . . . . .50 . . . . . . . . . . .t+1 . . . . . . . . . . . . .50t + 50 = 200<BR>\n" );
document.write( "Looking at column 3, we want to know when they meet, so the sum of the distances = 200, or<BR>\n" );
document.write( "60t + 50t + 50 = 200<BR>\n" );
document.write( "110t + 50 = 200<BR>\n" );
document.write( "110t = 150<BR>\n" );
document.write( "t = 1.181818 hours.<BR>\n" );
document.write( "which is ~ 1 hrs 22 min.<BR>\n" );
document.write( "or about 4:22 PM </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );