document.write( "Question 266754: A train traveling at 50 miles per hour leaves for a certain town. Two hours
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Algebra.Com's Answer #195943 by Edwin McCravy(20056)\"\" \"About 
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A train traveling at 50 miles per hour leaves for a certain town. Two hours
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document.write( "Make this chart\r\n" );
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document.write( "           DISTANCE      RATE      TIME\r\n" );
document.write( "TRAIN        \r\n" );
document.write( "BUS           \r\n" );
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document.write( "Let x be the required distance from where they started\r\n" );
document.write( "to the town.  They both traveled the same distance,\r\n" );
document.write( "so put x for both distances\r\n" );
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document.write( "           DISTANCE      RATE      TIME\r\n" );
document.write( "TRAIN         x         \r\n" );
document.write( "BUS           x        \r\n" );
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document.write( "Put in their rates which are given:\r\n" );
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document.write( "           DISTANCE      RATE      TIME\r\n" );
document.write( "TRAIN         x           50       \r\n" );
document.write( "BUS           x           60         \r\n" );
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document.write( "Now fill in the TIMES by using \"TIME=%28DISTANCE%29%2F%28RATE%29\"\r\n" );
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document.write( "           DISTANCE      RATE      TIME\r\n" );
document.write( "TRAIN         x           50       x/50\r\n" );
document.write( "BUS           x           60       x/60\r\n" );
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document.write( "The train's time was two hours more than the bus's time,\r\n" );
document.write( "so \r\n" );
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document.write( "   TRAIN'S TIME = BUS'S TIME + 2 HOURS\r\n" );
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document.write( "           x/50 =    x/60    +   2\r\n" );
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document.write( "\"x%2F50=x%2F60%2B2\"\r\n" );
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document.write( "Multiply through by 300\r\n" );
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document.write( "\"6x+=+5x%2B600\"\r\n" );
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document.write( "\"x=600\"\r\n" );
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document.write( "So the town is 600 miles from where they started.\r\n" );
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document.write( "Edwin
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