document.write( "Question 266661: 100=-(x-1)+4(x-6)
\n" );
document.write( "100=-x+-1+4x+-24
\n" );
document.write( "100=3x+-25?
\n" );
document.write( "I'm lost on this one? \n" );
document.write( "
Algebra.Com's Answer #195899 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "You are good so far except for one mistake in the second step. It would be two negatives in front of 1 to make it a positive 1. Here's the next step. (Hint: we want the x all alone on one side of the equal sign) \n" ); document.write( "100=-(x-1)+4(x-6) \n" ); document.write( "100=-x+1+4x-24 now combine like terms to get: \n" ); document.write( "100=3x+-23 Now we add 23 to both sides to give us: \n" ); document.write( "123=3x Divide both sides by 3 to get: \n" ); document.write( "x=41 \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "Hey-I wrote a book about the basics that might help: \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |