document.write( "Question 266646: Not sure if I am doing this correctly:
\n" ); document.write( "8(y+3)=3(2y+12)
\n" ); document.write( "8y+24=6y+36
\n" ); document.write( "2y+24=12
\n" ); document.write( "

Algebra.Com's Answer #195895 by drk(1908)\"\" \"About 
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\n" ); document.write( "\"8y%2B24=6y%2B36\"
\n" ); document.write( "next subtract 24 to get
\n" ); document.write( "\"8y+=+6y+%2B+12\"
\n" ); document.write( "subtract 6y to get
\n" ); document.write( " \"2y+=+12\"
\n" ); document.write( "divide to get
\n" ); document.write( "\"y+=+6\"
\n" ); document.write( "
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