document.write( "Question 266646: Not sure if I am doing this correctly:
\n" ); document.write( "8(y+3)=3(2y+12)
\n" ); document.write( "8y+24=6y+36
\n" ); document.write( "2y+24=12
\n" ); document.write( "

Algebra.Com's Answer #195894 by Alan3354(69443)\"\" \"About 
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Not sure if I am doing this correctly:
\n" ); document.write( "8(y+3)=3(2y+12)
\n" ); document.write( "8y+24=6y+36
\n" ); document.write( "2y+24=12 *** 2y = 12
\n" ); document.write( "------------
\n" ); document.write( "y = 6
\n" ); document.write( "
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