document.write( "Question 266580: train a and b is travelling in the same direction on parallel tracks. Train A is travelling at 40 miles per hour and train B is travelling at 48 miles per hour. Train A is passes the station at 6:25 A.M. If train B passes the station at 6:55A.M. at what time will train b catch up to train a. \n" ); document.write( "
Algebra.Com's Answer #195880 by ankor@dixie-net.com(22740)\"\" \"About 
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train a and b is traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 40 miles per hour and train B is traveling at 48 miles per hour.
\n" ); document.write( "Train A is passes the station at 6:25 A.M. If train B passes the station at 6:55A.M. at what time will train B catch up to train a.
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\n" ); document.write( "\n" ); document.write( "From the given information, we know that train B is 30 min (.5 hr) behind
\n" ); document.write( " train A, when train A passes the station.
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\n" ); document.write( "The distance between the trains at this time: .5 * 48 = 24 mi
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\n" ); document.write( "Let t = time required for train B to catch train A
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train B travel dist = Train A travel dist + 24 mi
\n" ); document.write( "48t = 40t + 24
\n" ); document.write( "48t - 40t = 24
\n" ); document.write( "8t = 24
\n" ); document.write( "t = \"24%2F8\"
\n" ); document.write( "t = 3 hrs
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\n" ); document.write( "6:25 + 3 hrs = 9:25 am, B catches A
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\n" ); document.write( "Check solution by finding the distances (train B travels 24 mi more than train A)
\n" ); document.write( "48 * 3 = 144 mi
\n" ); document.write( "40 * 3 = 120 mi
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\n" ); document.write( "difference = 24 mi
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