document.write( "Question 33171: A rectangular yard is surrounded by a fence that is 4 feet longer than it is wide. If the perimeter of the fence is 424 feet, what are the dimensions of the yard it encloses?\r
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document.write( "Wouldn't this just be 424 minus 4? \n" );
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Algebra.Com's Answer #19587 by mukhopadhyay(490)![]() ![]() ![]() You can put this solution on YOUR website! Width of the fence = x ft \n" ); document.write( "Length of the fence = x+4 \n" ); document.write( "Perimiter = 2(length+width) = 2(x+x+4) = 2(2x+4) = 4x+8; \n" ); document.write( "Perimeter = 424 ft \n" ); document.write( "=> 4x+8 = 424 \n" ); document.write( "=> 4x = 416 \n" ); document.write( "=> x = 104 \n" ); document.write( "Answer: The dimension of the fence is 108 ft X 104 ft \n" ); document.write( " |