document.write( "Question 266560: Solve by the substitution method
\n" ); document.write( "6m+n=23
\n" ); document.write( "m-6n=10
\n" ); document.write( "the solution is \n" ); document.write( "

Algebra.Com's Answer #195858 by drk(1908) $\"\"$ $\"About$

You can put this solution on YOUR website!
here is the original system:
\n" ); document.write( "(i) $\"6m+%2B+n+=+23\"$
\n" ); document.write( "(ii) $\"m+-+6n+=+10\"$
\n" ); document.write( "since we must use substitution, we can solve (i) for n and get
\n" ); document.write( "(iii) $\"n+=+-6m+%2B+23\"$
\n" ); document.write( "substitute (iii) into (ii) to get
\n" ); document.write( "(iv) $\"m+-+6%2A%28-6m+%2B+23%29+=+10\"$
\n" ); document.write( "distribute and simplify to get
\n" ); document.write( "(v) $\"m+%2B+36m++-+138+=+10\"$
\n" ); document.write( "combine like terms to get
\n" ); document.write( "(vi) $\"37m+-+138+=+10\"$
\n" ); document.write( "add 138 to get
\n" ); document.write( "(vii) $\"37m+=+148\"$
\n" ); document.write( "divide by 37 to get
\n" ); document.write( "(viii) $\"m+=+4\"$
\n" ); document.write( "now,
\n" ); document.write( " $\"n+=+-1\"$
\n" ); document.write( "So, we get
\n" ); document.write( "(4,-1) \n" ); document.write( "

\n" );