document.write( "Question 266551: Zack is 4 times the age as Salman. Zack is also 3 years old than Salaman. How old is Zack? \r
\n" ); document.write( "\n" ); document.write( "I saw someone solve this equation using divison. However, I am not used to that method. Could you show me how to solve it using exactly what's there, multiplication? Thanks.
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Algebra.Com's Answer #195840 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
Let z = Zack and s = Salman
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\n" ); document.write( "Zack is 4 times the age as Salman
\n" ); document.write( "translates as
\n" ); document.write( "(i) \"z+=+4s\"
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\n" ); document.write( "Zack is also 3 years older than Salaman
\n" ); document.write( "translates as
\n" ); document.write( "(ii) \"z+=+s+%2B+3\"
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\n" ); document.write( "actually substitution is better here.
\n" ); document.write( "put (i) into (ii) to get
\n" ); document.write( "(iii) \"4s+=+s+%2B+3\"
\n" ); document.write( "subtract s to get
\n" ); document.write( "(iv) \"3s+=+3\"
\n" ); document.write( "and now divide to get
\n" ); document.write( "(v) \"s+=+1\"
\n" ); document.write( "This means that salman = 1 and zack = 4
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