document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33157>Question 33157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pharmacists needs to obtain a 70% alcohol solution.  How many ounces of a 30% alcohol solution must be mixed with 40 ounces of an 80% alcohol solution to obtain a 70% alcohol solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19584 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the solution be x for 30%<BR>\n" );
document.write( "Let y=40-x be the solution for 80%<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "30x+80(40-x)=70(40)<BR>\n" );
document.write( "30x-80x=70(40)-80(40)<BR>\n" );
document.write( "-40x=-400<BR>\n" );
document.write( "x=10<BR>\n" );
document.write( "40-10=30<BR>\n" );
document.write( "Hence, about 10 ounces is needed for 30% and 30 ounces is needed ofr 80%.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );