document.write( "Question 266350: A couple has three children. Find each probability\r
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document.write( " A. All boys
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document.write( " B. All girls or all boys
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document.write( " C. Exactly two boys or two girls
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document.write( " D. At least one child of each gender \n" );
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Algebra.Com's Answer #195817 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A couple has three children. Find each probability \n" ); document.write( "A. P(All boys) = (1/2)^3 = 1/8 \n" ); document.write( "----------------------------------------------- \n" ); document.write( "B. P(All girls or all boys) = 1/8 + 1/8 = 1/4 \n" ); document.write( "----------------------------------------------- \n" ); document.write( "C. P(Exactly two boys or two girls) = 2*3C2(1/2)^2*(1/2) = 2*3*(1/8) = 3/4 \n" ); document.write( "--------------------------------------- \n" ); document.write( "D. P(At least one child of each gender) = 1 -P(all girls or all boys) \n" ); document.write( "= 1 - 1/4 = 3/4 \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |