document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=266497>Question 266497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a yield sign in the shape of an isosceles triangle is 22 feet. If the shortest side is 2 feet less than the other two sides, find the length of the shortest side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195805 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the length of the sides be a,a and b\r<BR>\n" );
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document.write( "given <BR>\n" );
document.write( "perimeter a+b+a=22 => 2a+b=22\r<BR>\n" );
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document.write( "and b=a-2 substituting this in the above eq.\r<BR>\n" );
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document.write( "we get 2a+a-2=22\r<BR>\n" );
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document.write( "=>  3a=24\r<BR>\n" );
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document.write( "=> a=8\r<BR>\n" );
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document.write( "so length of the shortest side = b= 8-2 = 6\r<BR>\n" );
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document.write( "length of the shortest side = 6 feet </SPAN>\n" );
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