document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=266462>Question 266462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pharmacist is making an antiseptic of iodine and alcohol. The iodine/alcohol mixture he now has is 5% iodine. He wants a mixture that is 6% iodine How much of 10% iodine solution and how much of the original antiseptic should he mix to make 50ml of the new antiseptic.\r<BR>\n" );
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document.write( "ps. it is solving for two variables and i need it it a box to set up the information. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195801 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 10% iodine solution needed<BR>\n" );
document.write( "Then 50-x=amount of the original antiseptic (5% iodine) needed\r<BR>\n" );
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document.write( "Now we know that the amount of pure iodine in the 10% solution (0.10x) plus the amount of pure iodine in the original antiseptic that is used (0.05(50-x)) has to equal the amount of pure iodine in the final mixture (0.06*50).  So, our equation to solve is:<BR>\n" );
document.write( "0.10x+0.05(50-x)=0.06*50 get rid of parens<BR>\n" );
document.write( "0.10x+2.5-0.05x=3  subtract 2.5 from each side<BR>\n" );
document.write( "0.10x+2.5-2.5-0.05x=3-2.5  collect like terms<BR>\n" );
document.write( "0.05x=0.5  divide each side by 0.05<BR>\n" );
document.write( "x=10 ml-----------------amount of 10% iodine needed<BR>\n" );
document.write( "50-x=50-10=40 ml -----amount of original antiseptic needed\r<BR>\n" );
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document.write( "CK 0.10*10+40*0.05=0.06*50<BR>\n" );
document.write( "1+2=3<BR>\n" );
document.write( "3=3\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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