document.write( "Question 266485: A new computer can process a company’s monthly payroll in 1 hour less time than the old computer. To really save time, the manager used both computers and finished the payroll in 3 hours. How long would it take the new computer to do the payroll by itself? \n" ); document.write( "
Algebra.Com's Answer #195800 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of time it takes the old computer working alone to do the payroll \n" ); document.write( "Then the old computer works at the rate of 1/x of the payroll per hour \n" ); document.write( "We are told that the new computer working alone can do the payroll in x-1 hours \n" ); document.write( "Then the new computer works at the rate of 1/(x-1) of the payroll per hour \n" ); document.write( "Together the two computers work at the rate of 1/x + 1/(x-1) of the payroll per hour \n" ); document.write( "We are also told that when both computers are used, they can do the job in 3 hours. \n" ); document.write( "So, together the computers work at the rate of 1/3 of the payroll per hour \n" ); document.write( "So, our equation to solve is: \n" ); document.write( "1/x + 1/(x-1)=1/3 multiply each term by 3*x*(x-1) \n" ); document.write( "3(x-1)+3x=x(x-1) simplify \n" ); document.write( "3x-3+3x=x^2-x or \n" ); document.write( "6x-3=x^2-x subtract 6x from and add 3 to both sides \n" ); document.write( "6x-6x-3+3=x^2-x-6x+3 collect like terms \n" ); document.write( "x^2-7x+3=0-----------Quadratic in standard form; solve using the quadratic formula \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another possible solution is: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "(1/6.55)+1/(5.55)=1/3 \n" ); document.write( "0.15267+0.18018=0.33333333 \n" ); document.write( "0.333~~~~~~0.333\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |