document.write( "Question 266438: please solve for x and y.\r
\n" ); document.write( "\n" ); document.write( "mixture problem.\r
\n" ); document.write( "\n" ); document.write( "1.a chemist want to make 75 liters of 16% acid solution.he is going to make it by mixing a 10% acid and a 25% acid solution.how many liters of each will he need?\r
\n" ); document.write( "\n" ); document.write( "please answer this problem right away.I NEED YOUR HELP
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Algebra.Com's Answer #195738 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
solve for x and y.
\n" ); document.write( "mixture problem.
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\n" ); document.write( "1.a chemist want to make 75 liters of 16% acid solution.
\n" ); document.write( "x + y = 75
\n" ); document.write( "y = (75-x); this form for substitution
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\n" ); document.write( "he is going to make it by mixing a 10% acid and a 25% acid solution.
\n" ); document.write( "an amt of acid equation
\n" ); document.write( ".10x + .25y = .16(75)
\n" ); document.write( "Replace y with (75-x)
\n" ); document.write( ".10x + .25(75 - x) = .16(75)
\n" ); document.write( ".10x + 18.75 - .25x = 12
\n" ); document.write( ".10x - .25x = 12 - 18.75
\n" ); document.write( "-.15x = -6.75
\n" ); document.write( ".15x = 6.75
\n" ); document.write( "x = \"6.75%2F.15\"
\n" ); document.write( "x = 45 liter of 10% acid
\n" ); document.write( "then
\n" ); document.write( "y = 75 - 45 = 30 liters of 25%
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\n" ); document.write( "Check in the original equation:
\n" ); document.write( ".10(45) + .25(30) = .16(75)
\n" ); document.write( "4.5 + 7.5 = 12\r
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