document.write( "Question 266438: please solve for x and y.\r
\n" );
document.write( "\n" );
document.write( "mixture problem.\r
\n" );
document.write( "\n" );
document.write( "1.a chemist want to make 75 liters of 16% acid solution.he is going to make it by mixing a 10% acid and a 25% acid solution.how many liters of each will he need?\r
\n" );
document.write( "\n" );
document.write( "please answer this problem right away.I NEED YOUR HELP
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #195738 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! solve for x and y. \n" ); document.write( "mixture problem. \n" ); document.write( ": \n" ); document.write( "1.a chemist want to make 75 liters of 16% acid solution. \n" ); document.write( "x + y = 75 \n" ); document.write( "y = (75-x); this form for substitution \n" ); document.write( ": \n" ); document.write( "he is going to make it by mixing a 10% acid and a 25% acid solution. \n" ); document.write( "an amt of acid equation \n" ); document.write( ".10x + .25y = .16(75) \n" ); document.write( "Replace y with (75-x) \n" ); document.write( ".10x + .25(75 - x) = .16(75) \n" ); document.write( ".10x + 18.75 - .25x = 12 \n" ); document.write( ".10x - .25x = 12 - 18.75 \n" ); document.write( "-.15x = -6.75 \n" ); document.write( ".15x = 6.75 \n" ); document.write( "x = \n" ); document.write( "x = 45 liter of 10% acid \n" ); document.write( "then \n" ); document.write( "y = 75 - 45 = 30 liters of 25% \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check in the original equation: \n" ); document.write( ".10(45) + .25(30) = .16(75) \n" ); document.write( "4.5 + 7.5 = 12\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |