document.write( "Question 266368: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train B is traveling at 110 miles per hour. Train A passes a station at 10:15 A.M. If train B passes the same station at 10:27 A.M., at what time will train B catch up to train A?\r
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document.write( "I know the equation is
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document.write( "100t = 110(t - something)\r
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document.write( "I know there is 12 minutes difference, but I do not know how to put 12 minutes in a decimal form.\r
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document.write( "Could someone please help me with this, I would appreciate it very much. \n" );
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Algebra.Com's Answer #195706 by checkley77(12844) ![]() You can put this solution on YOUR website! 100t=110(t-12/60) \n" ); document.write( "100t=110(t-1/5) \n" ); document.write( "100t=110t-22 \n" ); document.write( "100t-110t=-22 \n" ); document.write( "-10t=-22 \n" ); document.write( "t=-22/-10 \n" ); document.write( "t=2.2 hours after train A leaves the station they will meet. \n" ); document.write( "OR: 10:15+2:12=12.27 is the time of the meet. \n" ); document.write( "Proof: \n" ); document.write( "100*2.2=110(2.2-1/5) \n" ); document.write( "220=242-22 \n" ); document.write( "220=220 \n" ); document.write( " |