document.write( "Question 266268: Debby has seven coins in her coin purse: 1 quarter, 2 dimes, 3 nickels, and 1
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Algebra.Com's Answer #195672 by Edwin McCravy(20059) $\"\"$ $\"About$

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document.write( "Of the 7 coins there are 6 non-quarters. If she doesn't get\r\n" );
document.write( "the quarter, then the only way she could fail to get less\r\n" );
document.write( "than 25 cents would be to get 2 dimes and 1 nickel.  Since \r\n" );
document.write( "there are only 2 dimes, to fail she must get them both, and \r\n" );
document.write( "since there are 3 nickels she can get 2 dimes and 1 nickel \r\n" );
document.write( "exactly 3 ways. So the number of successful ways to get less \r\n" );
document.write( "than 25 cents is the number of ways to get any 3 of the the \r\n" );
document.write( "6 non-quarters minus the 3 ways to get 2 dimes and a nickel.\r\n" );
document.write( "That is,\r\n" );
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document.write( " (6C3 - 3) ways\r\n" );
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document.write( "The number of ways of getting any 3 of the coins is 7C3.\r\n" );
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document.write( "So the desired probability is \r\n" );
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document.write( "The correct choice is (A)\r\n" );
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document.write( "Edwin

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