document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=266265>Question 266265</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two opposite sides of a square are increased by twenty-five percent while the other two are decreased by forty percent. Find the percent of decrease in the area of the square.\r<BR>\n" );
document.write( "\n" );
document.write( "(A) 15% (B) 25% (C) 30% (D) 32.5% (E) none of these\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195650 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Two opposite sides of a square are increased by twenty-five percent while the other two are decreased by forty percent. Find the percent of decrease in the area of the square.<BR>\n" );
document.write( "Area of original square: s^2 where s is the length of a side<BR>\n" );
document.write( "Area of new rectangle:<BR>\n" );
document.write( "((5/4)s)((6/10)s) = (3/4)s^2<BR>\n" );
document.write( "Quantity of decrease = s^2 - (3/4)s^2 = (1/4) s^2<BR>\n" );
document.write( "% of decrease = [(1/4)s^2]/s^2 = 1/4 = 25%<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
document.write( "(A) 15% (B) 25% (C) 30% (D) 32.5% (E) none of these \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );