document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=266242>Question 266242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me in evaluating the following function or inverse; then write the ordered pair\r<BR>\n" );
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document.write( "f(x)=3x+1  and f^-1=(x-1)/3\r<BR>\n" );
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document.write( "f^-1(10)=\r<BR>\n" );
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document.write( "(? , ?)\r<BR>\n" );
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document.write( "Thank you so much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195647 by </B><A HREF=/tutors/aboutme.mpl?userid=asuar010><B>asuar010(338)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=asuar010><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=asuar010><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195647\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f^(-1)(10)=(10-1)/3 just substitute the 10 by the x.\r<BR>\n" );
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document.write( "f^(-1)(10)=9/3=3\r<BR>\n" );
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document.write( "so the ordered pair is (3,10). </SPAN>\n" );
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