document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=266249>Question 266249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the side of a square is decreased by 3 meters, the area is decreased by 45 square meters. Find the length of the original square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195637 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the side of original square be x meters\r<BR>\n" );
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document.write( "so area will be x^2 sq.mt\r<BR>\n" );
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document.write( "now given If the side of a square is decreased by 3 meters, the area is decreased by 45 square meters\r<BR>\n" );
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document.write( "so when the side is x-3 the area is (x-3)^2 that is given equal to x^2-45\r<BR>\n" );
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document.write( "so (x-3)^2 = x^2-45\r<BR>\n" );
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document.write( "=>   x^2-6x+9 = x^2-45\r<BR>\n" );
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document.write( "=>6x=54\r<BR>\n" );
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document.write( "so x=9\r<BR>\n" );
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document.write( "so the side of the original square is 9 meters in length </SPAN>\n" );
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