document.write( "Question 266232: The length of a rectangle is 6 cm longer than its width. If the perimeter is 40 cm, what is the area? \n" ); document.write( "

Algebra.Com's Answer #195632 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!

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\n" ); document.write( "\n" ); document.write( "Let us state the given:\r
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\n" ); document.write( "\n" ); document.write( "Width = ? = $\"x\"$
\n" ); document.write( "Length = $\"6cm+%2B+x+\"$
\n" ); document.write( "Perimeter = $\"40cm\"$ \r
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\n" ); document.write( "\n" ); document.write( "Knowing Perimeter of a Rectangle, substitute given:
\n" ); document.write( " $\"P%5BR%5D=2L+%2B+2W\"$
\n" ); document.write( " $\"40=2%286%2Bx%29%2B2%28x%29\"$
\n" ); document.write( " $\"40=12%2B2x%2B2x\"$
\n" ); document.write( " $\"40=12%2B4x\"$ ----> $\"4x=40-12\"$ ---> $\"4x=28\"$ ---> $\"cross%284%29x%2Fcross%284%29=cross%2828%297%2Fcross%284%29\"$
\n" ); document.write( " $\"x=7cm=Width\"$ \r
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\n" ); document.write( "\n" ); document.write( "For $\"Length=6cm%2B7cm=13cm\"$ \r
\n" ); document.write( "\n" ); document.write( "SO for the $\"AREA%5BR%5D+=+L+%2A+W+=+%2813cm%29%287cm%29\"$
\n" ); document.write( " $\"highlight%28red%28Area%5BR%5D=91cm%5E2%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo\r
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