document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33146>Question 33146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One of two supplementary angles is 4degrees more than 1/3 of the other angle.  Find the measure of each of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19563 by </B><A HREF=/tutors/aboutme.mpl?userid=sarah_adam><B>sarah_adam(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarah_adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of two supplementary angles are 180 degrees<BR>\n" );
document.write( "Let the two supplementary angles be x and y<BR>\n" );
document.write( "according to given condition let<BR>\n" );
document.write( "x = 4+ y*(1/3)<BR>\n" );
document.write( "But x+y = 180<BR>\n" );
document.write( "4+ y*(1/3) +y = 180<BR>\n" );
document.write( "(y+3y)/3 = 180 - 4<BR>\n" );
document.write( "4y/3 = 176<BR>\n" );
document.write( "4y = 176*3<BR>\n" );
document.write( "y =(176*3)/4<BR>\n" );
document.write( "y = 132 degrees<BR>\n" );
document.write( "x = 4 + y/3 = 4 +132/3<BR>\n" );
document.write( "x = 48 degrees<BR>\n" );
document.write( "x=48 degrees; y = 132 degrees<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );