document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33139>Question 33139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I HAVE A FEW QUESTION ON HOW TO DO THINGS\r<BR>\n" );
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document.write( "1.  82.1 G = ?KG\r<BR>\n" );
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document.write( "2. 12 SQ MM = ? SQ CM\r<BR>\n" );
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document.write( "3.4 CU M = ? CU DM \r<BR>\n" );
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document.write( "4.WHAT IS THE PERIMETER OF A SQUARE WHOSE SIDES MEASURE 26 CM\r<BR>\n" );
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document.write( "5. PERMITER OF  A RECTANGLE 41 M LONG AND 17 M WIDE\r<BR>\n" );
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document.write( "6.FIND THE CIRCUMFERENCE OF A CIRCLE WHOSE RADIUS IS 80FT\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19561 by </B><A HREF=/tutors/aboutme.mpl?userid=sarah_adam><B>sarah_adam(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarah_adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) 1 kg = 1000 g<BR>\n" );
document.write( "1 g = 1/1000 kg<BR>\n" );
document.write( "82.1 g = 82.1/1000 = 0.0821 kg\r<BR>\n" );
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document.write( "b)12 SQ MM = ? SQ CM <BR>\n" );
document.write( "1 sqmm = 100 sq cm<BR>\n" );
document.write( "12 sq mm = 12/100 sq cm = 0.12 sq cm\r<BR>\n" );
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document.write( "c)4 CU M = ? CU DM <BR>\n" );
document.write( "1000 cu. decimeters = 1 cu. meter <BR>\n" );
document.write( "4 CuM= 4000 Cu DM\r<BR>\n" );
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document.write( "d)WHAT IS THE PERIMETER OF A SQUARE WHOSE SIDES MEASURE 26 CM <BR>\n" );
document.write( "Perimeter of square = 4S<BR>\n" );
document.write( "where S = side of square = 26cm<BR>\n" );
document.write( "Perimeter = 4(26)= 104 cm\r<BR>\n" );
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document.write( "e)PERMITER OF A RECTANGLE 41 M LONG AND 17 M WIDE <BR>\n" );
document.write( "Perimeter of Rectangle : 2(L+W)<BR>\n" );
document.write( "P = 2(41+17)=116 M\r<BR>\n" );
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document.write( "f)FIND THE CIRCUMFERENCE OF A CIRCLE WHOSE RADIUS IS 80FT <BR>\n" );
document.write( "Circumference of circle = 2*pi*r<BR>\n" );
document.write( "where r = radius of circle,pi = 22/7 = 3.14<BR>\n" );
document.write( "C = 2*pi*(80)<BR>\n" );
document.write( "C= 160 (3.14) ft = 502.4 ft\r<BR>\n" );
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