document.write( "Question 266188: the perimeter of a rectangle is 24 ft. Its length is five times its width. Let x be the length and y be the width. What is the area of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #195607 by calegebra(14)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "P=2L+2W Length (here)=5y Width (here)=y Substitute Length and Width (here) into the Perimeter equation as in: P=2L+2W = 24 = 2(5y)+(y)=10y+y=11y \n" ); document.write( "If 11y=24 than y=24/11 that is width and x(length)=5y or 5(24/11) \n" ); document.write( " |