document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33125>Question 33125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify the following as much as possible leaved the answer in exact form:<BR>\n" );
document.write( "sin 225 degrees ctn 300 degrees + sec 150 degrees cos 315 degrees  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19559 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin 225 degrees ctn 300 degrees + sec 150 degrees cos 315 degrees<BR>\n" );
document.write( "={SIN(180+45)}*{COT(360-60)}+{SEC(180-30)}*{COS(360-45)}<BR>\n" );
document.write( "=-SIN(45)*{-COT(60)}+{-SEC(30)}*COS(45)<BR>\n" );
document.write( "=(1/SQRT.2)((1/SQRT.3)-(2/SQRT.3)(1/SQRT.2)<BR>\n" );
document.write( "=(1-2)/SQRT(3*2)=-1/SQRT.6=-SQRT.(6)/6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );