document.write( "Question 33137This question is from textbook college algebra
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document.write( ": An open-top box is to be constructed from a 6 by 8 foot rectangular cardboard by cutting out equal squares at each corner and the folding up the flaps. Let x denote the length of each side of the square to be cut out.
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document.write( "a)Find the function V that represents the volume of the box in terms of x.
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document.write( "b)Graph this function.
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document.write( "c)Using the graph, what is the value of x that will produce the maximum volume?
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document.write( "Thank you for your help. !!!!! ;') \n" );
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Algebra.Com's Answer #19558 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! I AM ABLE TO FIND ONE SUCH QUESTION I ANSWERED EARLIER.SEE THAT AND BY THE SIDE CORRESPONDING ANSWER TO YOUR QUESTION \n" ); document.write( "Volume/30504: an open box is to be constructed from a piece of cardboard 15 inches by 25 inches by cutting squares of length x from each corner and folding up the sides. Express the volume of the box as a function of x. what is the domain v? \n" ); document.write( "1 solutions .........IN YOUR CASE THE DIMENSIONS ARE 6' AND 8' \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Answer 17192 by venugopalramana(1167) About Me on 2006-03-17 06:08:55 (Show Source): \n" ); document.write( "an open box is to be constructed from a piece of cardboard 15 inches by 25 inches by cutting squares of length x from each corner and folding up the sides. Express the volume of the box as a function of x. what is the domain v? \n" ); document.write( "WHEN WE CUT X LONG PIECES ON ALL 4 SIDES THE CARD BOARD WILL GET REDUCED BY \n" ); document.write( "X+X=2X...ALONG LENGTH AND...X+X=2X.....ALONG WIDTH \n" ); document.write( "SO OPEN BOX LENGTH = 25-2X ..(IN YOUR CASE 8-2X) AND WIDTH = 15-2X..(IN YOUR CASE 6-2X)..AND HEIGHT =X ...SO VOLUME V IS GIVEN BY LEMGTH*WIDTH*HEIGHT \n" ); document.write( "V=(25-2X)(15-2X)X...(IN YOUR CASE (8-2X)(6-2X)X...DOMAIN OF V IS GIVEN BY THE FACT THAT LENGTH OR WIDTH CAN NOT BE NEGATIVE...CRITICAL VALUE BEING WIDTH WE GET .... \n" ); document.write( "15-2X>0...OR....15>2X...OR....7.5>X....OR X<7.5...(IN YOUR CASE 8-2X>0...AND 6-2X>0...SO X <3) \n" ); document.write( "RANGE.....MAXIMUM VALUE....IN YOUR CASE.... \n" ); document.write( "V=X(8-2X)(6-2X)=X{48-16X-12X+4X^2)=4X^3-28X^2+48X...IF YOU KNOW CALCULUS \n" ); document.write( "DV/DX=12X^2-56X+48=0..OR...3X^2-14X+12=0.... \n" ); document.write( "X=(14+SQRT.(52))/6...OR......(7+SQRT.(13))/3...OR....(7-SQRT.13)/3\r \n" ); document.write( "\n" ); document.write( "X=3.54..OR...1.13. \n" ); document.write( "D2V/DX2=6X-14=- VE AT X=1.13...SO MAXIMUM VOLUME IS OBTAINED AT X=1.13' \n" ); document.write( "YOU CAN SEE IT BY PLOTTING THE GRAPH.\r \n" ); document.write( "\n" ); document.write( " |