document.write( "Question 33135This question is from textbook college algebra
\n" ); document.write( ": I can not for the life of me remember how to do this. I have tried numerous ways and still have not come to the correct answer.\r
\n" ); document.write( "\n" ); document.write( "2x to the 4-3x to the 3+x+1 is divided by 2x to the 2+x+1 \n" ); document.write( "
Algebra.Com's Answer #19553 by mukhopadhyay(490)\"\" \"About 
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This math looks hard, but easy to solve.
\n" ); document.write( "[(2x)^(4-3x)]^(3+x+1) / [(2x)^(2+x+1)];
\n" ); document.write( "Based on the property (x^m)^(n) = x^(mn);
\n" ); document.write( "So,
\n" ); document.write( "[(2x)^(4-3x)]^(3+x+1) = (2x)^[(4-3x)(4+x)]
\n" ); document.write( "=> [(2x)^(4-3x)]^(3+x+1) = (2x)^(16+4x-12x-3x^2)
\n" ); document.write( "=> [(2x)^(4-3x)]^(3+x+1) = (2x)^(-3x^2-8x+16);
\n" ); document.write( ".................
\n" ); document.write( "Based on the property: x^m/x^n = x^(m-n);
\n" ); document.write( "We have the same base in the question and the common base is 2x;
\n" ); document.write( "Thus,
\n" ); document.write( "[(2x)^(4-3x)]^(3+x+1) / [(2x)^(2+x+1)] = [(2x)^(-3x^2-8x+16)] / [(2x)^(2+x+1)]
\n" ); document.write( "=> [(2x)^(4-3x)]^(3+x+1) / [(2x)^(2+x+1)] = (2x)^[(-3x^2-8x+16) - (3+x)]
\n" ); document.write( "=> [(2x)^(4-3x)]^(3+x+1) / [(2x)^(2+x+1)] = (2x)^[(-3x^2-9x+13)]
\n" ); document.write( "The answer is (2x)^[(-3x^2-9x+13)]
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