document.write( "Question 33132: I looked to see if any questions were like mine, I found one or two, but they had so much more information in them and it was a little confusing. So here is my question Thank You!\r
\n" ); document.write( "\n" ); document.write( "Question:
\n" ); document.write( "Dave Invested $17,000, part at 18% and part at 4%. If the total interest at the end of the year is $1,380, how much did he invest at each rate.\r
\n" ); document.write( "\n" ); document.write( "Thank You,
\n" ); document.write( "Trinia
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Algebra.Com's Answer #19547 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let's assume that Dave invested $x at 18% and the remainder ($17,000 - $x) at 4%.
\n" ); document.write( "The interest earned on the $x is: 18% of x
\n" ); document.write( "The interest earned on the remainder ($17,000 - $x) is: 4% of ($17,000 - $x).
\n" ); document.write( "The sum of these two amounts is: $1,380\r
\n" ); document.write( "\n" ); document.write( "So, if you change the percents to their decimal equivalents, you can write the equation which can then be solved for x.\r
\n" ); document.write( "\n" ); document.write( " $\"0.18x+%2B+0.04%2817000-x%29+=+1380\"$ Simplify and solve for x.
\n" ); document.write( " $\"0.18x+%2B+680+-+0.04x+=+1380\"$ Combine like-terms.
\n" ); document.write( " $\"0.14x+%2B+680+=+1380\"$ Subtract 680 from both sides of the equation.
\n" ); document.write( " $\"0.14x+=+700\"$ Divide both sides by 0.14
\n" ); document.write( " $\"x+=+5000\"$ \r
\n" ); document.write( "\n" ); document.write( "Dave invested $5,000 at 18% interest and ($17,000 - $5,000) $ 12,000 at 4% interest. \n" ); document.write( "

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