document.write( "Question 265954: The length a rectangle is 6 inches more than twice its width the perimeter is 72 inches what is the length and the width? \n" ); document.write( "
Algebra.Com's Answer #195452 by drk(1908)\"\" \"About 
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Let L = length and width
\n" ); document.write( "(i) L = 2W + 6
\n" ); document.write( "Let
\n" ); document.write( "(ii) P = 2L + 2W
\n" ); document.write( "which is
\n" ); document.write( "(iii) 72 = 2L + 2W
\n" ); document.write( "or
\n" ); document.write( "(iv) 36 = L + W
\n" ); document.write( "substituting (i) into (Iv) we get
\n" ); document.write( "(v) 36 = 2W + 6 + W
\n" ); document.write( "which is
\n" ); document.write( "36 = 3W + 6
\n" ); document.write( " and then 30 = 3W
\n" ); document.write( "so
\n" ); document.write( "W = 10 inches
\n" ); document.write( "L = 26 inches
\n" ); document.write( "
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