document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265899>Question 265899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant has coffee worth $20 a pound that she wishes to mix with 50 pounds of coffee worth $80 a pound to get a mixture that can be sold for $60 a pound. How many pounds of the $20 coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195427 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A merchant has coffee worth $20 a pound that she wishes to mix with 50 pounds of coffee worth $80 a pound to get a mixture that can be sold for $60 a pound. How many pounds of the $20 coffee should be used?\r<BR>\n" );
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document.write( "$20 coffee---------------------- $80 coffee------------------------- mix $60\r<BR>\n" );
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document.write( "x-50 ---------------------------------50------------------------------- x<BR>\n" );
document.write( "(x-50)*20 +50*80 =60x\r<BR>\n" );
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document.write( "20x-1000 +4000 = 60x\r<BR>\n" );
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document.write( "20x-60x= -4000 +1000<BR>\n" );
document.write( "-40x= -3000<BR>\n" );
document.write( "x= -3000/-40<BR>\n" );
document.write( "75 The mix will be 75 lbs\r<BR>\n" );
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document.write( "And $20 coffee will  be 75 -50  = 25lbs </SPAN>\n" );
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