document.write( "Question 265886: Square rote of 2 x square rote of 15 =
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Algebra.Com's Answer #195410 by JBarnum(2146) $\"\"$ $\"About$

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Square rote of 2 x square rote of 15 =
\n" ); document.write( " $\"%28sqrt%282%29%29%28sqrt%2815%29%29=x\"$
\n" ); document.write( " $\"%28sqrt%282%29%29%5E2%28sqrt%2815%29%29%5E2=x%5E2\"$
\n" ); document.write( " $\"2%2815%29=x%5E2\"$
\n" ); document.write( " $\"sqrt%2830%29=sqrt%28x%5E2%29\"$
\n" ); document.write( " $\"sqrt%2830%29=x\"$
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\n" ); document.write( "an easier example of this problem below will help you understand the method of solving this problem:
\n" ); document.write( " $\"%28sqrt%284%29%29%28sqrt%289%29%29=x\"$
\n" ); document.write( " $\"%28sqrt%284%29%29%5E2%28sqrt%289%29%29%5E2=x%5E2\"$
\n" ); document.write( " $\"4%289%29=x%5E2\"$
\n" ); document.write( " $\"sqrt%2836%29=sqrt%28x%5E2%29\"$
\n" ); document.write( " $\"6=x\"$ \r
\n" ); document.write( "\n" ); document.write( "Checking: since we know $\"sqrt%284%29=2\"$ and $\"sqrt%289%29=3\"$ , then $\"2%2A3=x\"$ , $\"6=x\"$
\n" ); document.write( "so this method of solving is correct\r
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