document.write( "Question 265852: A rectangle is 2 times as long as it is wide. If the area is 50 square feet, find its perimeter.
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Algebra.Com's Answer #195402 by JBarnum(2146)\"\" \"About 
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A rectangle is 2 times as long as it is wide. If the area is 50 square feet, find its perimeter.
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\n" ); document.write( "first off Perimeter(P)= 2 Length(L) + 2 Width(W)
\n" ); document.write( "P=2L+2W
\n" ); document.write( "and Area(A)=Langth(L) times Width(W)
\n" ); document.write( "A=LW
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\n" ); document.write( "so A=50 and L=2W
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\n" ); document.write( "A=LW
\n" ); document.write( "\"50=2W%28W%29%0D%0A%7B%7B%7B50%2F2=2%2F2%28W%5E2%29\"
\n" ); document.write( "\"sqrt%2825%29=sqrt%28W%5E2%29\"
\n" ); document.write( "\"5=W\"
\n" ); document.write( "L=2W
\n" ); document.write( "\"L=2%285%29\"
\n" ); document.write( "\"L=10\"
\n" ); document.write( "P=2L+2W
\n" ); document.write( "\"P=2%2810%29%2B2%285%29\"
\n" ); document.write( "\"P=%2820%2B10%29\"
\n" ); document.write( "\"P=30\"\r
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