document.write( "Question 265852: A rectangle is 2 times as long as it is wide. If the area is 50 square feet, find its perimeter.
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Algebra.Com's Answer #195402 by JBarnum(2146)![]() ![]() You can put this solution on YOUR website! A rectangle is 2 times as long as it is wide. If the area is 50 square feet, find its perimeter. \n" ); document.write( "____ \n" ); document.write( "first off Perimeter(P)= 2 Length(L) + 2 Width(W) \n" ); document.write( "P=2L+2W \n" ); document.write( "and Area(A)=Langth(L) times Width(W) \n" ); document.write( "A=LW \n" ); document.write( "____ \n" ); document.write( "so A=50 and L=2W \n" ); document.write( ". \n" ); document.write( "A=LW \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "L=2W \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "P=2L+2W \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |